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7b^2-49b=0
a = 7; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·7·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*7}=\frac{0}{14} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*7}=\frac{98}{14} =7 $
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